## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.8 - Exponents and Order of Operations - Exercise Set - Page 100: 65

14

#### Work Step by Step

24$\div$$\frac{3^2}{8-5}-(-6) 24\div$$\frac{3^2}{8-5}$+6 First solve the exponent 24$\div$$\frac{9}{8-5}+6 Then subtract in the denominator of the fraction 24\div$$\frac{9}{3}$+6 Then simplify the fraction 24$\div$3+6 Then divide (8)+6 Then add 14

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