Introductory Algebra for College Students (7th Edition)

$\displaystyle \frac{-20}{x}+\frac{3}{x}$, simplifies to $\displaystyle \frac{-17}{x}$
the quotient of $-20$ and a number ... $\rightarrow$... $\displaystyle \frac{-20}{x}$ ...which is increased by ... $\rightarrow \displaystyle \frac{-20}{x}+...$ .... the quotient of $3$ and a number$\quad\rightarrow \displaystyle \frac{-20}{x}+\frac{3}{x}.$ This simplifies, because the demominator is common, to, $...=\displaystyle \frac{ -20+3}{x}$ ... then, adding different signed numbers, we keep the sign of $-20$, because it has the greater absolute value, and subtract their absolute values: $=\displaystyle \frac{-(20-3)}{x}$ $=\displaystyle \frac{-17}{x}$