Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.5 - Addition of Real Numbers - Exercise Set: 31

Answer

$\frac{3}{10}$

Work Step by Step

$\frac{9}{10}$+(-$\frac{3}{5}$) $\frac{9}{10}$-($\frac{3\times2}{5\times2}$) $\frac{9}{10}$-($\frac{6}{10}$)=$\frac{3}{10}$
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