Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.5 - Addition of Real Numbers - Exercise Set - Page 63: 67


$-6x+(-13)x$, simplifies to $-19x$

Work Step by Step

the product of $-6$ and a number ... $\rightarrow$... $-6x$ ...which is increased by ... $\rightarrow -6x+...$ .... the product of $-13$ and a number$\quad\rightarrow -6x+(-13)x.$ This simplifies, first using the distributive property, $...=[ -6+(-13)]x$ ... then, adding same signed numbers, we keep the sign and add their absolute values: $=-(6+13)x$ $=-19x$
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