Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.3 - The Real Numbers - Exercise Set - Page 43: 111

Answer

Makes sense.

Work Step by Step

Not every square root results in an irrational number. For example, $h$ could have been 6. Then $\sqrt{1.5\cdot 6}=\sqrt{9}=3$ , which is a rational number (we can write it as $\displaystyle \frac{3}{1}).$ Makes sense.
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