#### Answer

5$^\circ$ C

#### Work Step by Step

C=$\frac{5}{9}$(F-32)
C=$\frac{5}{9}$(41-32)
C=$\frac{5}{9}$(9)
C=$\frac{5\times9}{9}=\frac{45}{9}=\frac{45\div9}{9\div9}$
C=5

Published by
Pearson

ISBN 10:
0-13417-805-X

ISBN 13:
978-0-13417-805-9

5$^\circ$ C

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