Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set - Page 30: 107

Answer

$x-\displaystyle \frac{1}{3}=\frac{1}{2}x$

Work Step by Step

$\left.\begin{array}{ccccc} \text{ a number } & \text{decreased by } & \frac{1}{3} & \text{is} & \text{ half of that number } & \\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \\ x & - & \frac{1}{3} & = & \text{ half of x } & \\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \\ x & - & \frac{1}{3} & = & \frac{1}{2}x & \end{array}\right.$ $x-\displaystyle \frac{1}{3}=\frac{1}{2}x$
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