Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set: 119

Answer

$\frac {4}{15}$

Work Step by Step

($\frac {1}{2}$-$\frac {1}{3}$)$\div$$\frac {5}{8}$ ($\frac {1\times3}{2\times3}$-$\frac {1\times2}{3\times2}$)$\div$$\frac {5}{8}$ ($\frac {3}{6}$-$\frac {2}{6}$)$\div$$\frac {5}{8}$ ($\frac {3-2}{6}$)$\div$$\frac {5}{8}$ ($\frac {1}{6}$)$\div$$\frac {5}{8}$ $\frac {1}{6}$$\times$$\frac {8}{5}$ $\frac {8}{30}=\frac {8\div2}{30\div2}=\frac {4}{15}$
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