## Introductory Algebra for College Students (7th Edition)

a. $8$ b. $8$ is not a solution of the equation
$a.$ Replace x with $3$ and y with $\displaystyle \frac{1}{2}$: $5x-14y=$ $=5\displaystyle \cdot 3-14\cdot\frac{1}{2}$ $=15-7$ $=8$ b. If the number $8$ is the solution to the equation, then replacing $w$ with $8$ should result in a valid equation (the left side should be equal to the right side of the equality sign) $4w=54-5w\quad?$ $4(8)=54-5(8)\quad?$ $32=54-40\quad?$ No, the equation is not valid, $8$ is not a solution of the equation.