## Introductory Algebra for College Students (7th Edition)

"quotient of y and $3$" $\rightarrow\quad \displaystyle \frac{y}{3}$ "1 less than the quotient of y and $3$" $\rightarrow\quad \displaystyle \frac{y}{3}-1$ "x is 1 less than the quotient of y and $3$" $\rightarrow\quad x=\displaystyle \frac{y}{3}-1$ If y=$15$, we calculate x from the last equation, $x=\displaystyle \frac{y}{3}-1\\=\dfrac{15}{3}-1\\=5-1\\=4$ To evaluate the expression, replace x with $4$ and y with $15$: $3x+4(y+6)=$ $=3(4)+4(15+6)$ $=12+4(21)$ $=12+84$ $=96$