## Intermediate Algebra for College Students (7th Edition)

Since, $\log_a A=\dfrac{\log A}{\log a}$ Let us write the correct statement such as: $\log_3 7=\dfrac{\log 7}{\log 3}$ or, $=\dfrac{1}{\dfrac{\log 3}{\log 7}}$ Since, $\log_a A=\dfrac{\log A}{\log a}$ or, $=\dfrac{1}{\log_7 3}$ Hence, the given statement is true.