Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set: 48

Answer

$\ln{(x^{\frac{1}{3}}y)}$

Work Step by Step

RECALL: (1) $\ln{a}-\ln{c} = \ln{(\frac{a}{c})}$ (2) $\ln{a} + \ln{c} = \ln{ac}$ (3) $a \cdot \ln{x} = \ln{x^{a}}$ Use rule (3) above to obtain: $=\ln{(x^{\frac{1}{3}})}+\ln{(y)}$ Use rule (2) above to obtain: $=\ln{(x^{\frac{1}{3}}y)}$
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