Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set - Page 713: 64

Answer

$\approx 1.4595$

Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_a{b} = \dfrac{\log{b}}{\log{a}}$ Use the formula above to obtain: $=\dfrac{\log{57.2}}{\log{16}}$ Use a calculator to evaluate to four decimal places: $\approx 1.4595$
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