Answer
no solution
Work Step by Step
Let $x^2 - 6x + 9 \lt 0$ be a function $f$.
Find the $x$-intercepts by solving $x^2 - 6x + 9=0$
Factor: $x^2 - 6x + 9$ = $(x-3)(x-3)$
$x-3=0$
$x = 3$
In this case, there is exactly one $x$-intercept. The graph of the quadratic equation does not cross the $x$-axis but will only touch it at point $(3,0)$.
Since we are interested in solving $f (x) < 0$, where $f(x) = x^2 - 6x + 9$, we cannot get any solution because the graph is never below the $x$-axis.
