Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.5 - Polynomial and Rational Inequalities - Exercise Set - Page 649: 28

Answer

$$(-∞,\frac{-4-\sqrt{71}}{5}]∪[\frac{-4+\sqrt{71}}{5},+∞)$$

Work Step by Step

Let $5x^2 +8x \geq 11 $ be a function $f$. Express the inequality in the form $f(x) \geq 0$. Begin by the rewriting the inequality so that $0$ is on the right side. $5x^2 +8x \geq 11$ $5x^2 +8x -11\geq 11-11$ $5x^2 +8x -11\geq 0 $ Find the $x$-intercepts by solving $5x^2 +8x -11=0$ Use the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$ where $a=5$, $b=8$, $c=-11$ $x = \frac{-8±\sqrt{8^2-4⋅5⋅-11}}{2⋅5}$ $x = \frac{-4-\sqrt{71}}{5}$ or $\frac{-4+\sqrt{71}}{5}$ These $x$-intercepts serve as boundary points that separate the number line into intervals. The boundary points of this equation therefore divide the number line into three intervals: $(-∞, \frac{-4-\sqrt{71}}{5})(\frac{-4-\sqrt{71}}{5},\frac{-4+\sqrt{71}}{5})(\frac{-4+\sqrt{71}}{5}, +∞)$ Choose one test value within each interval and evaluate $f$ at that number. $(-∞, \frac{-4-\sqrt{71}}{5})$ Test Value = $-3$ $f=5x^2 +8x -11$ $f=5(-3)^2 +8(-3) -11$ $f=10$ Conclusion: $f (x) > 0$ for all $x$ in $(-∞,\frac{-4-\sqrt{71}}{5})$. $(\frac{-4-\sqrt{71}}{5}, \frac{-4+\sqrt{71}}{5})$ Test Value = $0$ $f=5x^2 +8x -11$ $f=5(0)^2 +8(0) -11$ $f=-11$ Conclusion: $f (x) < 0$ for all $x$ in $(\frac{-4-\sqrt{71}}{5}, \frac{-4+\sqrt{71}}{5})$. $(\frac{-4+\sqrt{71}}{5},+∞)$ Test Value = $1$ $f=5x^2 +8x -11$ $f=5(1)^2 +8(1) -11$ $f=2$ Conclusion: $f (x) > 0$ for all $x$ in $(\frac{-4+\sqrt{71}}{5},+∞)$. Write the solution set, selecting the interval or intervals that satisfy the given inequality. We are interested in solving $f (x) \gt 0$, where $f (x) = 5x^2 +8x -11$. Based on the solution above, $f(x)\geq0$ for all $x$ in $(\frac{-4-\sqrt{71}}{5},-∞)$ or $(\frac{-4+\sqrt{71}}{5},+∞)$. However, because the inequality involves $\geq$ (greater than or equal to), we must also include the solutions of $5x^2+8x-11$, namely $\frac{-4-\sqrt{71}}{5}$ and $\frac{-4+\sqrt{71}}{5}$, in the solution set. Thus, the solution set of the given inequality is: $$(-∞,\frac{-4-\sqrt{71}}{5}]∪[\frac{-4+\sqrt{71}}{5},+∞)$$
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