Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.3 - Quadratic Functions and Their Graphs - Exercise Set - Page 626: 51

Answer

$ f(x)=2(x+10)^2-5$.

Work Step by Step

Given equation of the parabola is $f(x)=2x^2$. vertex $(h,k)=(-10,-5)$. The equation of the parabola that has the same shape is $\Rightarrow f(x)=2(x-h)^2+k$ Substitute the values of $h$ and $k$. $\Rightarrow f(x)=2(x-(-10))^2+(-5)$ Simplify. $\Rightarrow f(x)=2(x+10)^2-5$.
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