#### Answer

$1 - 8x^3 = (1 - 2x)(1 + 2x + 4x^2)$

#### Work Step by Step

$1 - 8x^3$
Express each term as the cube of some monomial. Then use the formula for factoring $A^3-B^3=(A-B)(A^2+AB+B^2)$.
$1 - (2x)^3$
A =1, B=2x
$1 - (2x)^3 = (1 - 2x)(1^2 + 1(2x) + (2x)^2)$
$1 - (2x)^3 = (1 - 2x)(1 + 2x + 4x^2)$