## Intermediate Algebra for College Students (7th Edition)

$1 - 8x^3 = (1 - 2x)(1 + 2x + 4x^2)$
$1 - 8x^3$ Express each term as the cube of some monomial. Then use the formula for factoring $A^3-B^3=(A-B)(A^2+AB+B^2)$. $1 - (2x)^3$ A =1, B=2x $1 - (2x)^3 = (1 - 2x)(1^2 + 1(2x) + (2x)^2)$ $1 - (2x)^3 = (1 - 2x)(1 + 2x + 4x^2)$