## Intermediate Algebra for College Students (7th Edition)

TRUE $(x - 5)^2 = 12$ Using the Square Root Property $u^2 = d$, then $u = \sqrt d$ or $u = - \sqrt d$. Thus, $x - 5 = ±\sqrt12$ $x -5 = ±\sqrt12$ $x -5= ±\sqrt(4⋅3)$ $x -5 = ±2\sqrt3$
$(x - 5)^2 = 12$ Using the Square Root Property $u^2 = d$, then $u = \sqrt d$ or $u = - \sqrt d$. Thus, $x - 5 = ±\sqrt12$ $x -5 = ±\sqrt12$ $x -5= ±\sqrt(4⋅3)$ $x -5 = ±2\sqrt3$