Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 596: 108



Work Step by Step

Need to solve for $y$. We have $\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$ This can be written in the form of $y$ as: $\dfrac{y^2}{b^2}=1-\dfrac{x^2}{a^2}$ or, $\dfrac{y}{b}=\sqrt{1-\dfrac{x^2}{a^2}}$ or, $y=b \sqrt{\dfrac{{a^2-x^2}}{a^2}}$ Hence, $y=\dfrac{b\sqrt{a^2-x^2}}{a}$
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