Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 524: 160



Work Step by Step

Since, equation of of two poits linear equation can be written as: $y-y_1=\dfrac{y_1-y_{2}}{x_1-x_2}(x-x_0)$ Then $y-1=\dfrac{1-3}{5-4}(x-5)$ or, $y-1=\dfrac{-2}{1}(x-5)$ or, $y-1=-2x+10$ Hence, $2x+y-11=0$
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