## Intermediate Algebra for College Students (7th Edition)

$2x+y-11=0$
Since, equation of of two poits linear equation can be written as: $y-y_1=\dfrac{y_1-y_{2}}{x_1-x_2}(x-x_0)$ Then $y-1=\dfrac{1-3}{5-4}(x-5)$ or, $y-1=\dfrac{-2}{1}(x-5)$ or, $y-1=-2x+10$ Hence, $2x+y-11=0$