Answer
$2x+y-11=0$
Work Step by Step
Since, equation of of two poits linear equation can be written as: $y-y_1=\dfrac{y_1-y_{2}}{x_1-x_2}(x-x_0)$
Then $y-1=\dfrac{1-3}{5-4}(x-5)$
or, $y-1=\dfrac{-2}{1}(x-5)$
or, $y-1=-2x+10$
Hence, $2x+y-11=0$
