Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 524: 141

Answer

$\sqrt[6] {x^5}$.

Work Step by Step

The given expression is $=\sqrt[3] x\cdot \sqrt x$ Rewrite as exponential expressions. $=(x)^{\frac{1}{3}}\cdot (x)^{\frac{1}{2}}$ To multiply with the same base, add exponents. $=(x)^{\frac{1}{3}+\frac{1}{2}}$ Write exponents in terms of the LCD, $6$. $=(x)^{\frac{2}{6}+\frac{3}{6}}$ Add exponents. $=(x)^{\frac{2+3}{6}}$ Simplify. $=(x)^{\frac{5}{6}}$ Rewrite as a radical expression: $=\sqrt[6] {x^5}$.
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