## Intermediate Algebra for College Students (7th Edition)

$61$
Simplify. $[3+(27^{2/3} +32^{2/5}]^{3/2}-9^{1/2}$ This can be written as: $[3+(27^{2/3} +32^{2/5}]^{3/2}-9^{1/2}=[3+(3^3)^{2/3} +(2^5)^{2/5}]^{3/2}-9^{1/2}$ and $=[16]^{3/2}-9^{1/2}$ or, $=64-3$ or, $=61$