Answer
$61$
Work Step by Step
Simplify. $[3+(27^{2/3} +32^{2/5}]^{3/2}-9^{1/2}$
This can be written as:
$[3+(27^{2/3} +32^{2/5}]^{3/2}-9^{1/2}=[3+(3^3)^{2/3} +(2^5)^{2/5}]^{3/2}-9^{1/2}$
and $=[16]^{3/2}-9^{1/2}$
or, $=64-3$
or, $=61$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 524: 158
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