Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 489: 38

Answer

$72\;ergs $.

Work Step by Step

Step 1:- Translate the statement to form an equation. Let kinetic energy is $E$, the mass is $M$, and velocity is $V$. $\Rightarrow E=kMV^2$ ...... (1) Step 2:- Substitute the first set of values into the equation to find the value of $k$. The given values are $M=8\; grams,V=3\; centimeters\; per \; second$ and $E=36\; ergs$. Substitute into the equation (1). $\Rightarrow 36=k(8)(3)^2$ Simplify. $\Rightarrow 36=72k$ Divide both sides by $72$. $\Rightarrow \frac{36}{72}=\frac{72k}{72}$ Simplify. $\Rightarrow 0.5=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=0.5$ into the equation (1). $\Rightarrow E=0.5MV^2$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $M=4\; grams$ and $V=6\; centimeters\;per\;seconds$ into the equation (2). $\Rightarrow E=0.5(4)(6)^2$ Simplify. $\Rightarrow E=72$ Hence, the kinetic energy is $72\;ergs $.
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