## Intermediate Algebra for College Students (7th Edition)

$5x^{2}+4x+11+ \displaystyle \frac{33}{x-2}$
Dividing with $x-c\qquad...\qquad c=2.$ $\begin{array}{rrrrrr} \underline{2}| &5 &-6 &3 &11 &\\ & &10 &8 &22 &\\ & --&--&--&--&\\ &5 &4 &11 &33 &\end{array}$ Quotient = $5x^{2}+4x+11$ Remainder = $33$ $\displaystyle \frac{dividend}{divisor}=quotient+\frac{remainder}{divisor}$ $\displaystyle \frac{5x^{3}-6x^{2}+3x+11}{x-2}$ = $5x^{2}+4x+11+ \displaystyle \frac{33}{x-2}$