Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.3 - Complex Rational Expressions - Exercise Set - Page 435: 9

Answer

$\frac{1}{x-3}$.

Work Step by Step

The given expression is $=\frac{\frac{1}{x-2}}{1-\frac{1}{x-2}}$ Multiply the numerator and the denominator by $(x-2)$. $=\frac{(x-2)}{(x-2)}\cdot \frac{\frac{1}{x-2}}{1-\frac{1}{x-2}}$ Use the distributive property. $=\frac{(x-2)\cdot\frac{1}{x-2}}{(x-2)\cdot (1)-(x-2)\cdot \frac{1}{x-2}}$ Simplify. $=\frac{1}{x-2-1}$ $=\frac{1}{x-3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.