Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.3 - Complex Rational Expressions - Exercise Set - Page 435: 13

Answer

$-x$.

Work Step by Step

The given expression is $=\frac{\frac{4}{x+4}}{\frac{1}{x+4}-\frac{1}{x}}$ Multiply the numerator and the denominator by $x(x+4)$. $=\frac{x(x+4)}{x(x+4)}\cdot \frac{\frac{4}{x+4}}{\frac{1}{x+4}-\frac{1}{x}}$ Use the distributive property. $=\frac{x(x+4) \cdot \frac{4}{x+4}}{x(x+4) \cdot\frac{1}{x+4}-x(x+4) \cdot\frac{1}{x}}$ Simplify. $=\frac{4x}{x-(x+4) }$ $=\frac{4x}{x-x-4 }$ $=\frac{4x}{-4 }$ $=-x$.
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