Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.3 - Complex Rational Expressions - Exercise Set - Page 435: 1

Answer

$\dfrac{4x+2}{x-3}$

Work Step by Step

Given: $\dfrac{4+\dfrac{2}{x}}{1-\dfrac{3}{x}}$ Let us consider the numerator expression $4+\dfrac{2}{x}=\dfrac{4x+2}{x}$ ...(1) Now, we will consider the denominator expression. $1-\dfrac{3}{x}=\dfrac{x-3}{x}$ ...(2) Divide equation (1) by (2). Hence, $\dfrac{4+\dfrac{2}{x}}{1-\dfrac{3}{x}}=\dfrac{4x+2}{x-3}$
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