Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 429: 88

Answer

$(x+10)(x-10)^2$

Work Step by Step

We factor each denominator: $$\begin{align*} x^2-100&=(x-10)(x+10)\\ x^2-20x+100&=(x-10)^2. \end{align*}$$ The Least Common Denominator (LCD) is the product of all factors in the two denominators, each taken once at the highest exponent: $$(x+10)(x-10)^2.$$
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