Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 429: 85

Answer

$\dfrac{2x(2x+15)}{(x+7)(x+8)}$

Work Step by Step

We are given the rectangle with the dimensions: $$\begin{align*} \text{Length}&=\dfrac{x}{x+7}\\ \text{Width}&=\dfrac{x}{x+8}. \end{align*}$$ We determine the perimeter of the rectangle: $$\begin{align*} \text{Perimeter}&=2\cdot\text{Length}+2\cdot\text{Width}\\ &=2\cdot\dfrac{x}{x+7}+2\cdot \dfrac{x}{x+8}\\ &=\dfrac{2x}{x+7}+\dfrac{2x}{x+8}\\ &=\dfrac{2x(x+8)+2x(x+7)}{(x+7)(x+8)}\\ &=\dfrac{2x(x+8+x+7)}{(x+7)(x+8)}\\ &=\dfrac{2x(2x+15)}{(x+7)(x+8)}. \end{align*}$$
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