## Intermediate Algebra for College Students (7th Edition)

$\dfrac{x+1}{4x-3}$
Since,in the given rational expressions denominator are same, thus take it as common and subtract the rational terms by changing the sign of each term of the second rational. Given: $\dfrac{3x}{4x-3}-\dfrac{2x-1}{4x-3}$ or, $=\dfrac{3x-(2x-1)}{4x-3}$ or, $=\dfrac{3x-2x+1}{4x-3}$ or, $=\dfrac{x+1}{4x-3}$