Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 426: 6

Answer

$\dfrac{2x+3}{x+5}$

Work Step by Step

Since,in the given rational expressions denominator are same, thus take it as common and add the rational terms simply. Given: $\dfrac{x^2+7x}{x^2-5x}+\dfrac{x^2-4x}{x^2-5x}$ or, $=\dfrac{x^2+7x+x^2-4x}{x^2-5x}$ or, $=\dfrac{2x^2+3x}{x^2-5x}$ or, $=\dfrac{x(2x+3)}{x(x-5)}$ or, $=\dfrac{2x+3}{x+5}$
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