Answer
$\dfrac{2x+3}{x+5}$
Work Step by Step
Since,in the given rational expressions denominator are same, thus take it as common and add the rational terms simply.
Given: $\dfrac{x^2+7x}{x^2-5x}+\dfrac{x^2-4x}{x^2-5x}$
or, $=\dfrac{x^2+7x+x^2-4x}{x^2-5x}$
or, $=\dfrac{2x^2+3x}{x^2-5x}$
or, $=\dfrac{x(2x+3)}{x(x-5)}$
or, $=\dfrac{2x+3}{x+5}$
