Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 426: 8

Answer

$\dfrac{(y-5)}{(y+5)}$

Work Step by Step

Since,in the given rational expressions denominator are same, thus take it as common and add the rational terms simply. Given: $\dfrac{y^2}{y^2-25}+\dfrac{25-10y}{y^2-25}$ or, $=\dfrac{y^2-10y+25}{y^2-25}$ or, $=\dfrac{(y-5)^2}{y^2-5^2}$ or, $=\dfrac{(y-5)^2}{(y-5)(y+5)}$ or, $=\dfrac{(y-5)}{(y+5)}$
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