Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 413: 6

Answer

-3/5, -1/4, 15/8

Work Step by Step

$\frac{2(-1)^3-1}{(-1)^2+4} = \frac{-2-1}{5} = -\frac{3}{5}$ $\frac{2(-1)^3-1}{(-1)^2+4} = \frac{-2-1}{5} = -\frac{1}{4}$ $\frac{2(2)^3-1}{(2)^2+4} = \frac{2(8)-1}{4+4} = \frac{15}{8}$
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