## Intermediate Algebra for College Students (7th Edition)

a: $\frac{2(-1)^3-5}{(-1)^2+1} = \frac{-2-5}{1+1} = -\frac{7}{2}$ b: $\frac{2(0)^3-5}{(0)^2+1} = \frac{-5}{1} = -5$ c: $\frac{2(2)^3-5}{(2)^2+1} = \frac{2(8)-5}{4+1} = \frac{11}{5}$