Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 413: 4


a: 0 b: undefined c: -3

Work Step by Step

a: $\frac{(-1)^2-3(-1)-4}{3-(-1)} = \frac{1+3-4}{4} = 0$ b: $\frac{(3)^2-3(3)-4}{3-(3)} = \frac{-4}{0}$ is undefined c: $\frac{(5)^2-3(5)-4}{3-(5)} = \frac{25-15-4}{-2} = -3$
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