## Intermediate Algebra for College Students (7th Edition)

a: $\frac{(-1)^2-3(-1)-4}{3-(-1)} = \frac{1+3-4}{4} = 0$ b: $\frac{(3)^2-3(3)-4}{3-(3)} = \frac{-4}{0}$ is undefined c: $\frac{(5)^2-3(5)-4}{3-(5)} = \frac{25-15-4}{-2} = -3$