Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Mid-Chapter Check Point - Page 447: 16

Answer

$ \frac{7x+4}{4(x+1)}$.

Work Step by Step

The given expression is $=\frac{\frac{3}{x+1}+\frac{4}{x}}{\frac{4}{x}}$ Multiply the numerator and denominator by $x(x+1)$. $=\frac{x(x+1)}{x(x+1)}\cdot \frac{\frac{3}{x+1}+\frac{4}{x}}{\frac{4}{x}}$ Use the distributive property. $= \frac{x(x+1)\cdot\frac{3}{x+1}+x(x+1)\cdot\frac{4}{x}}{x(x+1)\cdot\frac{4}{x}}$ Simplify. $= \frac{3x+4(x+1)}{4(x+1)}$ $= \frac{3x+4x+4}{4x+4}$ $= \frac{7x+4}{4x+4}$ $= \frac{7x+4}{4(x+1)}$.
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