Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Mid-Chapter Check Point - Page 447: 4

Answer

$\frac{5x-3}{x-2}$

Work Step by Step

$5+\frac{7}{x-2}=\frac{5(x-2)}{x-2}+\frac{7}{x-2}=\frac{5(x-2)+7}{x-2}=\frac{5x-3}{x-2}$
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