Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 392: 74



Work Step by Step

As per question, we have $(a+2)^2=36$ or, $a^2+4+4a-36=0$ or, $a^2+4a-32=0$ or, $a^2+8a-4a-32=0$ Thus, $(a-4)(a+8)=0$ This implies $a=-8,4$ Since, the side of a square cannot be negative, thus our answer is: $4$
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