## Intermediate Algebra for College Students (7th Edition)

$4$
As per question, we have $(a+2)^2=36$ or, $a^2+4+4a-36=0$ or, $a^2+4a-32=0$ or, $a^2+8a-4a-32=0$ Thus, $(a-4)(a+8)=0$ This implies $a=-8,4$ Since, the side of a square cannot be negative, thus our answer is: $4$