Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 392: 73

Answer

$5$ inches.

Work Step by Step

Let the length of the side of the square be $L$. Increased length = $L+3$. $A=(length)^2$. Thus: $A=(L+3)^2$ From the question we have $A=64$ square inches. $64=(L+3)^2$ $8^2=(L+3)^2$ Take the square root of both sides. $\pm \sqrt{8^2}=\sqrt{(L+3)^2}$ Simplify. $\pm 8=L+3$ This gives: $+ 8=L+3$ Subtract $3$ from both sides. $+ 8-3=L+3-3$ Simplify. $5=L$.
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