Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 392: 71

Answer

$l=9$ and $b=6$

Work Step by Step

Formula to calculate the area of a rectangle, $A= l \times b$ Here, $l= b+3$ Thus, $A= (b+3) \times b =b^2+3b$ or, $b^2+3b=54$ or, $b^2+3b-54=0$ This implies $b^2+9b-6b-54=0$ or, $(b+9)(b-6)=0$ Thus, $b=-9,6$; $A \neq -negative$ Hence, $l=b+3=6+3=9$ and $b=6$
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