Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 34

Answer

$2y(1-x^3y)(1+x^3y)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $m^2-n^2=(m-n)(m+n)$ Factor out the greatest common factor, $2y$, to obtain: $=2y(1-x^6y^2) \\=2y[1^2-(x^3y)^2]$ The binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $m=1$ and $n=x^3y$ to obtain: $=2y(1-x^3y)(1+x^3y)$
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