Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 363: 138

Answer

$(5,\infty)$.

Work Step by Step

The given compound inequality is $-2x\leq6$ and $-2x+3\lt-7$. Solve each inequality separately. First $-2x\leq6$. Divide both sides by $-2$ and change the sense of the inequality. $\Rightarrow \frac{-2x}{-2}\geq\frac{6}{-2}$ Simplify. $\Rightarrow x\geq-3$ Second $-2x+3\lt-7$. Subtract $3$ from both sides. $\Rightarrow -2x+3-3\lt-7-3$ Simplify. $\Rightarrow -2x\lt-10$ Divide both sides by $-2$ and change the sense of inequality. $\Rightarrow \frac{-2x}{-2}\gt\frac{-10}{-2}$ Simplify. $\Rightarrow x\gt5$ First graph and then take the intersection of the two inequality. We can write the compound inequality. $x\geq-3$ as $[-3,\infty)$ and $x\gt5$ as $(5,\infty)$ The intersection is $[-3,\infty)\cap(5,\infty)=(5,\infty)$. The combined graph is shown below.
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