Answer
$(x^3-5)(x^3-2)$.
Work Step by Step
The given expression is
$=x^6-7x^3+10$
The exponent $x^3$ is half that of the exponent $y^6$.
Rewrite the expression as shown below.
$=(x^3)^2-7x^3+10$
Substitute $x^3=u$.
$=(u)^2-7(u)+10$
Simplify.
$=u^2-7u+10$
Rewrite the term $-7u$ as $-5u-2u$.
$=u^2-5u-2u+10$
Group terms
$=(u^2-5u)+(-2u+10)$
Factor from each group.
$=u(u-5)-2(u-5)$
Factor out $(u-5)$.
$=(u-5)(u-2)$.
Substitute back $u=x^3$.
$=(x^3-5)(x^3-2)$.
