Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 363: 115

Answer

$(x^3-2)(x^3-5)$

Work Step by Step

$x^6-7x^3+10=x^6-2x^3-5x^3+10=x^3(x^3-2)-5(x^3-2)=(x^3-2)(x^3-5)$
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