Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 348: 78

Answer

$(x^2+y^2-z^2)(a+b+c)$.

Work Step by Step

The given expression is $=ax^2+ay^2-az^2+bx^2+by^2-bz^2+cx^2+cy^2-cz^2$ Factor out the common terms. $=a(x^2+y^2-z^2)+b(x^2+y^2-z^2)+c(x^2+y^2-z^2)$ Again factor out the common terms. $=(x^2+y^2-z^2)(a+b+c)$.
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