#### Answer

$(1+4y)(x^3-5)$

#### Work Step by Step

$x^3-5+4x^3y-20y=\\=x^3+4x^3y-5-20y\\=x^3(1+4y)-5(1+4y)\\=(1+4y)(x^3-5)$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$(1+4y)(x^3-5)$

$x^3-5+4x^3y-20y=\\=x^3+4x^3y-5-20y\\=x^3(1+4y)-5(1+4y)\\=(1+4y)(x^3-5)$

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