Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 348: 74

Answer

$y^8(3x-2)^6(9xy-6y-5)$.

Work Step by Step

The given expression is $=3y^9(3x-2)^7-5y^8(3x-2)^6$ Factor out the common factor $y^8(3x-2)^6$ from both terms. $=y^8(3x-2)^6[3y(3x-2)-5]$ Simplify. $=y^8(3x-2)^6(9xy-6y-5)$.
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