Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Mid-Chapter Check Point - Page 364: 3

Answer

$30x^5y^3-35x^3y^2-2x^2y$

Work Step by Step

$5x^2y(6x^3y^2-7xy-\frac{2}{5})=5x^2y\cdot6x^3y^2-5x^2y\cdot7xy-5x^2y\cdot\frac{2}{5}=30x^5y^3-35x^3y^2-2x^2y$
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