Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Mid-Chapter Check Point - Page 364: 18

Answer

$(x+y+5)^2=x^2+2xy+y^2+10x+10y+25$.

Work Step by Step

The given expression is $(x+y+5)^2$ Use the algebraic identity $(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca$ We have $a=x,b=y$ and $c=5$. The expression will be. $(x+y+5)^2=x^2+y^2+5^2+2(x)(y)+2(y)(5)+2(5)(x)$ Simplify. $(x+y+5)^2=x^2+y^2+25+2xy+10y+10x$ Rearrange. $(x+y+5)^2=x^2+2xy+y^2+10x+10y+25$.
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