Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Mid-Chapter Check Point - Page 364: 15



Work Step by Step

$(x^2-3)(x^3+5x+2)=x^2\cdot x^3+x^2\cdot5x+x^2\cdot2+(-3)\cdot x^3+(-3)\cdot5x+(-3)\cdot2=x^5+5x^3+2x^2-3x^3-15x-6=x^5+2x^3+2x^2-15x-6$
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